JEE Mains · Maths · STD 11 - 14. probability
Let \(A\) be the event that the absolute difference between two randomly choosen real numbers in the sample space \([0,60]\) is less than or equal to \(a\). If \(P(A)=\frac{11}{36}\), then \(a\) is equal to \(...............\).
- A \(100\)
- B \(0.1\)
- C \(15\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
\(|x-y| < a \Rightarrow-a < x-y < a\) \(\Rightarrow x-y < a \text { and } x-y > -a\) \(P ( A )=\frac{\operatorname{ar}( OACDEG )}{( OBDF )}\) \(=\frac{\operatorname{ar}( OBDF )-\operatorname{ar}( ABC )-\operatorname{ar}( EFG )}{\operatorname{ar}( OBDF )}\)…
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