JEE Mains · Maths · STD 12 - 10. vector algebra
Let \( \vec{a}, \vec{b}, \vec{c} \) be three vectors such that \( \vec{a}\times\vec{b}=2(\vec{a}\times\vec{c}) \). If \( |\vec{a}|=1, {|\vec{b}|}=4, |\vec{c}|=2 \), and the angle between \( \vec{b} \) and \( \vec{c} \) is \( 60^{\circ} \), then \( |\vec{a} \cdot \vec{c}| \) is:
- A 2
- B 4
- C 0
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\(\overrightarrow{ a } \times \overrightarrow{ b }-2(\overrightarrow{ a } \times \overrightarrow{ c })=0\) \(\overrightarrow{ a } \times(\overrightarrow{ b }-2 \overrightarrow{ c })=0 \Rightarrow \overrightarrow{b}-2 \overrightarrow{ c }=\lambda \overrightarrow{ a }\) ...(1)…
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