JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let \(B\) be the centre of the circle \(x^{2}+y^{2}-2 x+4 y+1=0\) Let the tangents at two points \(\mathrm{P}\) and \(\mathrm{Q}\) on the circle intersect at the point \(\mathrm{A}(3,1)\). Then \(8.\) \(\left(\frac{\text { area } \triangle \mathrm{APQ}}{\text { area } \triangle \mathrm{BPQ}}\right)\) is equal to .... .
- A \(18\)
- B \(36\)
- C \(72\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(18\)
Step-by-step Solution
Detailed explanation
\(\tan \theta=\frac{3}{2}\) \(\frac{\text { Area } \Delta \mathrm{APQ}}{\text { Area } \Delta \mathrm{BPQ}}=\frac{\mathrm{AR}}{\mathrm{RB}}=\frac{3 \sin \theta}{2 \cos \theta}=\frac{9}{4}\)…
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