JEE Mains · Maths · STD 12 - 2. inverse trigonometric function
If the domain of the function \(f(x)=\cos ^{-1}\left(\frac{2-|x|}{4}\right)+\left(\log _e(3-x)\right)^{-1}\) is \([-\alpha, \beta)-\{y\}\), then \(\alpha+\beta+\gamma\) is equal to :
- A \(12\)
- B \(9\)
- C \(11\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(11\)
Step-by-step Solution
Detailed explanation
\( -1 \leq\left|\frac{2-|x|}{4}\right| \leq 1 \) \( \Rightarrow\left|\frac{2-|x|}{4}\right| \leq 1 \) \( -4 \leq 2-|x| \leq 4 \) \( -6 \leq-|x| \leq 2 \) \( -2 \leq|x| \leq 6 \) \( |x| \leq 6 \) \( \Rightarrow x \in[-6,6]\) \(................(1)\) Now, \(3-x \neq 1\) And…
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