JEE Mains · Maths · STD 11 - 4.1 complex nubers
Let \(a, b\) be two real numbers such that \(a b < 0\). If the complex number \(\frac{1+ ai }{ b + i }\) is of unit modulus and \(a+i b\) lies on the circle \(|z-1|=|2 z|\), then a possible value of \(\frac{1+[ a ]}{4 b }\), where \([ t ]\) is greatest integer function, is :
- A \(-\frac{1}{2}\)
- B \(-1\)
- C \(1\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) \(-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(a b < 0\left|\frac{1+a i}{b+i}\right|=1\) \(|1+a i l=| b+i l\) \(a^2+1=b^2+1 \Rightarrow a=\pm b \Rightarrow b=-a \quad \text { as } a b < 0\) \((a, b) \text { lies on }| z -1|=|2 z |\) \(la + ib -1 \mid=2 l a + ibl\) \(( a -1)^2+ b ^2=4\left( a ^2+ b ^2\right)\)…
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