JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\overrightarrow{\mathrm{a}}\) and \(\overrightarrow{\mathrm{b}}\) be two vectors such that \(|2 \vec{a}+3 \vec{b}|=|3 \vec{a}+\vec{b}|\) and the angle between \(\vec{a}\) and \(\vec{b}\) is \(60^{\circ}\). If \(\frac{1}{8} \vec{a}\) is a unit vector, then \(|\vec{b}|\) is equal to :
- A \(4\)
- B \(6\)
- C \(5\)
- D \(8\)
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
\(|3 \vec{a}+\vec{b}|^{2}=|2 \vec{a}+3 \vec{b}|^{2}\) \((3 \vec{a}+\vec{b}) \cdot(3 \vec{a}+\vec{b})=(2 \vec{a}+3 \vec{b}) \cdot(2 \vec{a}+3 \vec{b})\)…
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