JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Let \(A =\left[\begin{array}{cc}1 & -1 \\ 2 & \alpha\end{array}\right]\) and \(B =\left[\begin{array}{ll}\beta & 1 \\ 1 & 0\end{array}\right], \alpha, \beta \in R\). Let \(\alpha_{1}\) be the value of \(\alpha\) which satisfies \(( A + B )^{2}= A ^{2}+\left[\begin{array}{ll}2 & 2 \\ 2 & 2\end{array}\right]\) and \(\alpha_{2}\) be the value of \(\alpha\) which satisfies \(( A + B )^{2}= B ^{2}\). Then \(\left|\alpha_{1}-\alpha_{2}\right|\) is equal to.
- A \(2\)
- B \(22\)
- C \(3\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(A+B=\left[\begin{array}{cc}\beta+1 & 0 \\ 3 & \alpha\end{array}\right]\) \((A+B)^{2}=\left[\begin{array}{cc}\beta+1 & 0 \\ 3 & \alpha\end{array}\right]\left[\begin{array}{cc}\beta+1 & 0 \\ 3 & \alpha\end{array}\right]\)…
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