JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The product of all the rational roots of the equation \(\left(x^2-9 x+11\right)^2-(x-4)(x-5)=3\), is equal to
- A \(14\)
- B \(21\)
- C \(28\)
- D \(7\)
Answer & Solution
Correct Answer
(A) \(14\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \left(x^2-9 x+11\right)^2-(x-4)(x-5)=3 \\ & \left(x^2-9 x+11\right)^2-\left(x^2-9 x+20\right)=3 \end{aligned}\) Let \(x^2-9 x+11=t\)…
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