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JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(\vec{a} = \sqrt{7}\hat{i} + \hat{j} - \hat{k}\) and \(\vec{b} = \hat{j} + 2\hat{k}\). If \(\vec{r}\) is a vector such that \(\vec{r} \times \vec{a} + \vec{a} \times \vec{b} = \vec{0}\) and \(\vec{r} \cdot \vec{a} = 0\), then \(|3\vec{r}|^2\) is equal to:

  1. A \(44\)
  2. B \(54\)
  3. C \(86\)
  4. D \(132\)
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Answer & Solution

Correct Answer

(A) \(44\)

Step-by-step Solution

Detailed explanation

Given \(\vec{r} \times \vec{a} + \vec{a} \times \vec{b} = \vec{0}\) \(\Rightarrow \vec{r} \times \vec{a} - \vec{b} \times \vec{a} = \vec{0}\) \(\Rightarrow (\vec{r} - \vec{b}) \times \vec{a} = \vec{0}\) \(\Rightarrow \vec{r} - \vec{b} = \lambda \vec{a}\)…
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