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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

If \(\mathrm{x}=2 \sin \theta-\sin 2 \theta\) and \(\mathrm{y}=2 \cos \theta-\cos 2 \theta\) ; \(\theta \in[0,2 \pi],\) then \(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\) at \(\theta=\pi\) is :

  1. A \(\frac{3}{2}\)
  2. B \(-\frac{3}{4}\)
  3. C \(\frac{3}{4}\)
  4. D \(\frac{3}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{3}{8}\)

Step-by-step Solution

Detailed explanation

\(x=2 \sin \theta-\sin 2 \theta\) \(\Rightarrow \frac{d x}{d \theta}=2 \cos \theta-2 \cos 2 \theta=4 \sin \left(\frac{\theta}{2}\right) \sin \left(\frac{3 \theta}{2}\right)\) \(y=2 \cos \theta-\cos 2 \theta\)…
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