JEE Mains · Maths · STD 12 - 8. Application and integration
The area of the bounded region enclosed by the curve \(y=3-\left|x-\frac{1}{2}\right|-|x+1|\) and the \(x-\)axis is
- A \(\frac{9}{4}\)
- B \(\frac{45}{16}\)
- C \(\frac{27}{8}\)
- D \(\frac{63}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{27}{8}\)
Step-by-step Solution
Detailed explanation
\(y =\left\{\begin{array}{ll}3+( x +1)+\left( x -\frac{1}{2}\right), & x <-1 \\ 3-( x +1)+\left( x -\frac{1}{2}\right), & -1 \leq x<\frac{1}{2} \\ 3-( x +1)-\left( x -\frac{1}{2}\right), & \frac{1}{2} \leq x \end{array}\right.\)…
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