JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Let \(A\,(4, -4)\) and \(B\,(9,6)\) be points on the parabola \(y^2 = 4x\) . Let \(C\) be chosen on the arc \(AOB\) of the parabola, where \(O\) is the origin, such that the area of \(\Delta ACB\) is maximum. Then, the area (in sq. units) of \(\Delta ACB,\) is
- A \(31\frac{3}{4}\)
- B \(32\)
- C \(30\frac{1}{2}\)
- D \(31\frac{1}{4}\)
Answer & Solution
Correct Answer
(D) \(31\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
For maximum area, tangent at the point \(c\) must be parallet to chord \(BC\). \(\therefore t = \frac{1}{2}\)
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