JEE Mains · Maths · STD 12 - 1. relation and function
Let \(A=\{-2,-1,0,1,2,3\}\). let R be a relation on A defined by \(x R y\) if and only if \(y=\max \{x, 1\}\). Let \(l\) be the number of elements in R. Let m and n be the minimum number of elements required to be added in R to make it reflexive and symmetric relations, respectively. Then \(l+\mathrm{m}+\mathrm{n}\) is equal to
- A \(12\)
- B \(11\)
- C \(13\)
- D \(14\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{A}=\{-2,-1,0,1,2,3\} \\ & \mathrm{R}=\{(-2,1),(-1,1),(0,1),(1,1),(2,2),(3,3)\} \\ & \ell=6 \\ & \mathrm{m}=3 \\ & \mathrm{n}=3 \\ & \ell+\mathrm{m}+\mathrm{n}=12\end{aligned}\)
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