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JEE Mains · Maths · STD 11 - 8. sequence and series

Let \(A_1\) and \(A_2\) be two arithmetic means and \(G_1, G_2\), \(G _3\) be three geometric means of two distinct positive numbers. The \(G _1^4+ G _2^4+ G _3^4+ G _1^2 G _3^2\) is equal to

  1. A \(2\left( A _1+ A _2\right) G _1 G _3\)
  2. B \(\left(A_1+A_2\right)^2 G_1 G_3\)
  3. C \(\left( A _1+ A _2\right) G _1^2 G _3^2\)
  4. D \(2\left( A _1+ A _2\right) G _1^2 G _3^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left(A_1+A_2\right)^2 G_1 G_3\)

Step-by-step Solution

Detailed explanation

\(a , A _1, A _2, b\) are in A.P. \(d =\frac{b-a}{3} ; A_1=a+\frac{b-a}{3}=\frac{2 a+b}{3}\) \(A_2=\frac{a+2 b}{3}\) \(A_1+A_2=a+b\) \(a, G_1, G_2, G_3, b \text { are in G.P. }\) \(r=\left(\frac{b}{a}\right)^{\frac{1}{4}}\) \(G_1=\left(a^3 b\right)^{\frac{1}{4}}\)…
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