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JEE Mains · Maths · STD 11 - 4.1 complex nubers

If \(z\) is a complex number such that  \(\left| z \right| \ge 2\) , then the minimum value of \(\left| {z + \frac{1}{2}} \right|\): 

  1. A is strictly greater than \(\frac{5}{2}\) 
  2. B is strictly greater than \(\;\frac{3}{2}\) but less than \(\frac{5}{2}\) 
  3. C is equal to  \(\frac{5}{2}\)
  4. D lie in the interval \((1,2)\) 
Verified Solution

Answer & Solution

Correct Answer

(D) lie in the interval \((1,2)\) 

Step-by-step Solution

Detailed explanation

\(|z| \geq 2\) is the region on or outside circle whose centre is \((0,0)\) and the radius is \(2\) . Minimum \(\left|z+\frac{1}{2}\right|\) is distance of \(z\), which lies on circle \(|z|=2\) from \(\left(-\frac{1}{2}, 0\right)\) therefore, minimum…
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