JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Let \(A\) be a \(3 \times 3\) real matrix such that \(A^2(A-2 I)-\) \(4(\mathrm{~A}-\mathrm{I})=\mathrm{O}\), where I and O are the identity and null matrices, respectively. If \(A^5=\alpha A^2+\beta A+\gamma I\), where \(\alpha, \beta\) and \(\gamma\) are real constants, then \(\alpha+\beta+\gamma\) is equal to:
- A \(12\)
- B \(20\)
- C \(76\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & A^3-2 A^2-4 A+4 I=0 \\ & A^3=2 A^2+4 A-4 I \\ & A^4=2 A^3+4 A^2-4 A \\ & =2\left(2 A^2+4 A-4 I\right)+4 A^2-4 A \\ & A^4=8 A^2+4 A-8 I \\ & A^5=8 A^3+4 A^2-8 A \\ & =8\left(2 A^2+4 A-4 I\right)+4 A^2-8 A \\ & A^5=20 A^2+24 A-32 I \\ & \therefore \alpha=20,…
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