JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Let \(C\) be the largest circle centred at \((2,0)\) and inscribed in the ellipse \(=\frac{x^2}{36}+\frac{y^2}{16}=1\).If \((1, \alpha)\) lies on \(C\), then \(10 \alpha^2\) is equal to \(.........\)
- A \(117\)
- B \(116\)
- C \(118\)
- D \(125\)
Answer & Solution
Correct Answer
(C) \(118\)
Step-by-step Solution
Detailed explanation
Equation of normal of ellipse \(\frac{x^2}{36}+\frac{y^2}{16}=1\) at any point \(P (6 \cos \theta, 4 \sin \theta)\) is \(3 \sec \theta x-2 \operatorname{cosec} \theta y=10\) this normal is also the normal of the circle passing through the point \((2,0)\) So, \(6 \sec \theta=10\)…
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