JEE Mains · Maths · STD 12 - 10. vector algebra
If \(\overrightarrow{ x }\) and \(\overrightarrow{ y }\) be two non-zero vectors such that \(|\overrightarrow{ x }+\overrightarrow{ y }|=|\overrightarrow{ x }|\) and \(2 \overrightarrow{ x }+\lambda \overrightarrow{ y }\) is perpendicular to \(\overrightarrow{ y },\) then the value of \(\lambda\) is
- A \(1\)
- B \(3\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
\(|\vec{x}+\vec{y}|=|\vec{x}|\) \(\sqrt{|\overrightarrow{ x }|^{2}+|\overrightarrow{ y }|^{2}+2 \overrightarrow{ x } \cdot \overrightarrow{ y }}=|\overrightarrow{ x }|\) \(|\overrightarrow{ y }|^{2}+2 \overrightarrow{ x } \cdot \overrightarrow{ y }=0\) Now…
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