JEE Mains · Maths · STD 12 - 9. differential equations
At present, a firm is manufacturing \(2000\) items. It is estimated that the rate of change of production \(P\) w.r.t. additional number of workers \(x\) is given by \(\frac{{dp}}{{dx}} = 100 - 12\sqrt x \) . If the firm employs \(25 \) more workers, then the new level of production of itmes is
- A \(2500\)
- B \(3000\)
- C \(3500\)
- D \(4500\)
Answer & Solution
Correct Answer
(C) \(3500\)
Step-by-step Solution
Detailed explanation
\(\mathrm{dP}=(100-12 \sqrt{x}) \mathrm{d} x\) By integrating \(\int \mathrm{dP}=\int(100-12 \sqrt{x}) \mathrm{d} x\) \(P=100 x-8 x^{3/2}+C\) When \(x=0\) then \(P=2000\) \(\Rightarrow \mathrm{C}=2000\) Now when \(x=25\) then \(P\) is…
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