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JEE Mains · Maths · STD 11 - 8. sequence and series
If three positive numbers \(a, b\) and \(c\) are in \(A.P.\) such that \(abc\, = 8\), then the minimum possible value of \(b\) is
- A \(2\)
- B \(4^{\frac{1}{3}}\)
- C \(4^{\frac{2}{3}}\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
By Arithmetic Mean: \(a + c\, = 2b\) Consider \(a\, = b\, = c\, = 2\) \( \Rightarrow \) \(abc\, = 8\) \( \Rightarrow \) \(a + b\, = 2b\) minimum possible value of \(b\, = 2\)
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