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JEE Mains · Maths · STD 11 - 9. straight line
The sides of a rhombus \(ABCD\) are parallel to the lines, \(x - y + 2\, = 0\) and \(7x - y + 3\, = 0\). If the diagonals of the rhombus intersect at \(P( 1, 2)\) and the vertex \(A\) ( different from the origin) is on the \(y\) axis, then the ordinate of \(A\) is
- A \(2\)
- B \(\frac{7}{4}\)
- C \(\frac{7}{2}\)
- D \(\frac{5}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{2}\)
Step-by-step Solution
Detailed explanation
Let the coordinate \(A\) be \((0,c)\) Equations of the given lines are \(x-y+2=0\) \(7x-y+3=0\) we know that the diagonals of the rhombus will be parallel to the angle bisectors of the two given lines; \(y=x+2\) and \(y=7x+3\) \(\therefore \) equation of angle bisectors is given…
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