JEE Mains · Maths · STD 11 - 4.1 complex nubers
If the set \(R=\{(a, b) ; a+5 b=42, a, b \in \mathbb{N}\}\) has \(m\) elements and \(\sum_{n=1}^m\left(1-i^{n !}\right)=x+i y\), where \(I=\sqrt{-1}\), then the value of \(m+x+y\) is :
- A \(8\)
- B \(12\)
- C \(4\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
\( a+5 b=42, a, b \in N \) \( a=42-5 b, b=1, a=37 \) \( b=2, a=32 \) \( b=3, a=27 \) \( \vdots \) \( b=8, a=2 \) \( R \text { has "8" elements } \Rightarrow \mathrm{m}=8 \) \( \sum_{n=1}^8\left(1-i^{n !}\right)=x+i y \) \( \text { for } n \geq 4, i^{n !}=1 \)…
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