JEE Mains · Maths · STD 11 - 9. straight line
A ray of light coming from the point \(P(1,2)\) gets reflected from the point \(\mathrm{Q}\) on the \(\mathrm{x}\)-axis and then passes through the point \(R(4,3)\). If the point \(S(h\), \(\mathrm{k})\) is such that \(\mathrm{PQRS}\) is a parallelogram, then \(\mathrm{hk}^2\) is equal to
- A \(80\)
- B \(90\)
- C \(60\)
- D \(70\)
Answer & Solution
Correct Answer
(D) \(70\)
Step-by-step Solution
Detailed explanation
Image of \(\mathrm{P}\) wrt \(\mathrm{x}\)-axis will be \(\mathrm{P}^{\prime}(1,-2)\) equation of line joining P'R will be \(\mathrm{y}-3=\frac{5}{3}(\mathrm{x}-4)\) Above line will meet \(\mathrm{x}\)-axis at \(\mathrm{Q}\) where…
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