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JEE Mains · Maths · STD 12 - 6. Application of derivatives

If the local maximum value of the function \(f(x)=\left(\frac{\sqrt{3 e}}{2 \sin x}\right)^{\sin ^2 x}, \quad x \in\left(0, \frac{\pi}{2}\right)\), is \(\frac{k}{e}\), then \(\left(\frac{ k }{ e }\right)^8+\frac{ k ^8}{ e ^5}+ k ^8\) is equal to

  1. A \(e^5+e^6+e^{11}\)
  2. B \(e^3+e^5+e^{11}\)
  3. C \(e ^3+ e ^6+ e ^{11}\)
  4. D \(e^3+e^6+e^{10}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(e ^3+ e ^6+ e ^{11}\)

Step-by-step Solution

Detailed explanation

\(\text { Let } y=\left(\frac{\sqrt{3 e}}{2 \sin x}\right)^{\sin ^2 x}\) \(\ln y=\sin ^2 x \cdot \ln \left(\frac{\sqrt{3 e}}{2 \sin x}\right)\)…
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