JEE Mains · Maths · STD 11 - 9. straight line
The shortest distance between the point \(\left( {\frac{3}{2},0} \right)\) and the curve \(y = \sqrt x ,\left( {x > 0} \right)\), is
- A \(\frac{{\sqrt 5 }}{2}\)
- B \(\frac{{\sqrt 3 }}{2}\)
- C \(\frac{3}{2}\)
- D \(\frac{5}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{{\sqrt 5 }}{2}\)
Step-by-step Solution
Detailed explanation
Let \(P\) be the point nearest to \(\left( {\frac{3}{2},0} \right)\), then normal at \(P\) will pass through \(\left( {\frac{3}{2},0} \right)\). Let Co-ordinates of \(P\) be \(s\left( {\frac{{{t^2}}}{4},\frac{t}{2}} \right)\) Hence equation of normal is…
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