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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

If the eccentricity \(e\) of the hyperbola \(\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1\), passing through \((6, 4\sqrt{3})\), satisfies \(15(e^2 + 1) = 34e\), then the length of the latus rectum of the hyperbola \(\dfrac{x^2}{b^2} - \dfrac{y^2}{2(a^2+1)} = 1\) is:

  1. A \(10\)
  2. B \(20\)
  3. C \(25\)
  4. D \(30\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(10\)

Step-by-step Solution

Detailed explanation

The given equation of the hyperbola is \(\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1\). Since it passes through \((6, 4\sqrt{3})\), we have: \(\dfrac{36}{a^2} - \dfrac{48}{b^2} = 1\) The eccentricity \(e\) satisfies \(15(e^2 + 1) = 34e\). \(15e^2 - 34e + 15 = 0\)…