JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
If the area of an equilateral triangle inscribed in the circle, \(x^2 + y^2 + 10x + 12y + c = 0\) is \(27\sqrt 3 \,sq.\,units\) then \(c\) is equal to
- A \(13\)
- B \(20\)
- C \(-25\)
- D \(25\)
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\(r = \sqrt {25 + 36 - c} = \sqrt {36}\) \(c = 25\)
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