JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\quad \vec{a}=9 \hat{i}-13 \hat{j}+25 \hat{k}, \vec{b}=3 \hat{i}+7 \hat{j}-13 \hat{k} \quad\) and \(\overrightarrow{\mathrm{c}}=17 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+\hat{\mathrm{k}}\) be three given vectros. If \(\overrightarrow{\mathrm{r}}\) is a vector such that \(\vec{r} \times \vec{a}=(\vec{b}+\vec{c}) \times \vec{a}\) and \(\vec{r} .(\vec{b}-\vec{c})=0\), then \(\frac{|593 \vec{r}+67 \vec{a}|^2}{(593)^2}\) is equal to ...........
- A \(105\)
- B \(107\)
- C \(570\)
- D \(569\)
Answer & Solution
Correct Answer
(D) \(569\)
Step-by-step Solution
Detailed explanation
\( \overrightarrow{\mathrm{a}}=9 \hat{\mathrm{i}}-13 \hat{\mathrm{j}}+25 \hat{\mathrm{k}} \) \( \overrightarrow{\mathrm{b}}=3 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}-13 \hat{\mathrm{k}} \) \( \overrightarrow{\mathrm{c}}=17 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+\hat{\mathrm{k}} \)…
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