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JEE Mains · Maths · STD 12 - 7.1 indefinite integral

Let \(\int x^3 \sin x \mathrm{~d} x=g(x)+C\), where \(C\) is the constant of integration. If \(8\left(g\left(\frac{\pi}{2}\right)+g^{\prime}\left(\frac{\pi}{2}\right)\right)=\alpha \pi^3+\beta \pi^2+\gamma, \alpha, \beta, \gamma \in Z\), then \(\alpha+\beta-\gamma\) equals :

  1. A 48
  2. B 55
  3. C 62
  4. D 47
Verified Solution

Answer & Solution

Correct Answer

(B) 55

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \int x^3 \sin x d x=-x^3 \cos x+\int 3 x^2 \cos x d x \\ & =-x^3 \cos x+3 x^2 \sin x-\int 6 x \sin x d x \\ & =-x^3 \cos x+3 x^2 \sin x+6 x \cos x-6 \sin x+c \end{aligned}\) So \(g(x)=-x^3 \cos x+3 x^2 \sin x+6 x \cos x-6 \sin x\)…
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