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JEE Mains · Maths · STD 12 - 7.1 indefinite integral

If \(f\left( {\frac{{3x - 4}}{{3x + 4}}} \right) = x + 2,\,x \ne -\frac{4}{3}\) , and \(\int {f\left( x \right)dx = A\,\log \left| {1 - x} \right| + Bx + C} \) , then the ordered pair \((A,B) \) is equal to : (where \(C\) is a constant of integration)

  1. A \(\left( {\frac{8}{3},\frac{2}{3}} \right)\)
  2. B \(\left( { - \frac{8}{3},\frac{2}{3}} \right)\)
  3. C \(\left( { - \frac{8}{3}, - \frac{2}{3}} \right)\)
  4. D \(\left( {\frac{8}{3}, - \frac{2}{3}} \right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left( { - \frac{8}{3},\frac{2}{3}} \right)\)

Step-by-step Solution

Detailed explanation

\(f\left(\frac{3 x-4}{3 x+4}\right)=x+2, x \neq-\frac{4}{3}\) Consider \(\frac{3 x-4}{3 x+4}=t\) \(3 x-4=3 t x+4 t\) \(x=\frac{4 t+4}{3-3 t}+2\) \(f(t)=\frac{10-2 t}{3-3 t}\) \(f(x) = \frac{{2x - 10}}{{3x - 3}}\) \(\int f (x)dx = \int {\frac{{2x - 10}}{{3x - 3}}} dx\)…
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