JEE Mains · Maths · STD 12 - 7.2 definite integral
Let the domain of the function
\(f(\mathrm{x})=\log _2 \log _4 \log _6\left(3+4 x-x^2\right)\) be \((\mathrm{a}, \mathrm{~b})\). If \(\int_0^{\mathrm{b}-\mathrm{a}}\left[\mathrm{x}^2\right] \mathrm{dx}=\mathrm{p}-\sqrt{\mathrm{q}}-\sqrt{\mathrm{r}}, \mathrm{p}, \mathrm{q},\) \(\mathrm{r} \in \mathbb{N}, \operatorname{gcd}(\mathrm{p}, \mathrm{q}, \mathrm{r})=1,\)
where [\(\cdot]\) is the greatest integer function, then \(\mathrm{p}+\mathrm{q}+\mathrm{r}\) is equal to
- A \(10\)
- B \(8\)
- C \(11\)
- D \(9\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
\(\log _4 \log _6\left(3+4 x-x^2\right) \gt 0 \) \( \log _6\left(3+4 x-x^2\right) \gt 1\) \(3+4 x-x^2 \gt 6 \) \( x^2-4 x+3 \lt 0 \) \( (x-1)(x-3) \lt 0 \) \( x \in(1,3) \) \( \text {so } a=1 b=3 \) \( \Rightarrow \int_0^2\left[x^2\right] d x=? \)…
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