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JEE Mains · Maths · STD 12 - 2. inverse trigonometric function

If \(\sin(\tan^{-1}(x\sqrt{2})) = \cot(\sin^{-1}\sqrt{1-x^2})\), \(x \in (0,1)\), then the value of \(x\) is :

  1. A \(\dfrac{1}{2}\)
  2. B \(\dfrac{1}{3}\)
  3. C \(\dfrac{2}{3}\)
  4. D \(\dfrac{5}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\dfrac{1}{2}\)

Step-by-step Solution

Detailed explanation

Let \(\alpha = \tan^{-1}(x\sqrt{2}) \Rightarrow \tan\alpha = x\sqrt{2}\) From the right-angled triangle, \(\sin\alpha = \dfrac{x\sqrt{2}}{\sqrt{1+2x^2}}\) Let \(\beta = \sin^{-1}\sqrt{1-x^2} \Rightarrow \sin\beta = \sqrt{1-x^2}\) From the right-angled triangle,…