JEE Mains · Maths · STD 11 - 8. sequence and series
If \(\frac{1}{2 \cdot 3^{10}}+\frac{1}{2^{2} \cdot 3^{9}}+\ldots \frac{1}{2^{10} \cdot 3}=\frac{K}{2^{10} \cdot 3^{10}}\), then the remainder when \(K\) is divided by \(6\) is
- A \(1\)
- B \(2\)
- C \(3\)
- D \(5\)
Answer & Solution
Correct Answer
(D) \(5\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2 \cdot 3^{10}}+\frac{1}{2^{2} \cdot 3^{9}}+\frac{1}{2^{3} \cdot 3^{8}}+\ldots .+\frac{1}{2^{10} \cdot 3}=\frac{K}{2^{10} \cdot 3^{10}}\) \(K=2^{9}+2^{8} \cdot 3+2^{7} \cdot 3^{2}+\ldots . .+3^{9}\)…
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