JEE Mains · Maths · STD 11 - 3. trignometrical ratios,functions and identities
If \(tan\, A\) and \(tan\, B\) are the roots of the quadratic equation, \(3x^2 - 10x - 25 = 0\) then the value of \(3\, sin^2\, (A +B)- 10\, sin\,(A +B). cos\,(A+ B)- 25\, cos^2\, (A+B)\) is
- A \(25\)
- B \(-25\)
- C \(-10\)
- D \(10\)
Answer & Solution
Correct Answer
(B) \(-25\)
Step-by-step Solution
Detailed explanation
\(\text { Given, } 3 x ^2-10 x -25=0\) \(\tan A+\tan B=\frac{10}{3}\) \(\tan A \times \tan B=\frac{-25}{3}\) \(\tan (A+B)=\frac{\tan A+\tan B}{1-\tan A \tan B}\) \(\frac{\frac{10}{3}}{1+\frac{25}{3}}\) \(\frac{\frac{10}{3}}{\frac{28}{3}}=\frac{10}{28}=\frac{5}{14}\)…
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