JEE Mains · Maths · STD 11 - 4.1 complex nubers
Let \(P=\{z \in \mathbb{C}:|z+2-3 i| \leq 1\}\) and \(Q=\{z \in \mathbb{C}: z(1+i)+\bar{z}(1-i) \leq-8\}\). Let in \(\mathrm{P} \cap \mathrm{Q},|\mathrm{z}-3+2 \mathrm{i}|\) be maximum and minimum at \(z_1\) and \(z_2\) respectively. If \(\left|z_1\right|^2+2|z|^2=\alpha+\beta \sqrt{2}\), where \(\alpha, \beta\) are integers, then \(\alpha+\beta\) equals ...........
- A \(30\)
- B \(35\)
- C \(36\)
- D \(40\)
Answer & Solution
Correct Answer
(C) \(36\)
Step-by-step Solution
Detailed explanation
Clearly for the shaded region \(z_1\) is the intersection of the circle and the line passing through \(\mathrm{P}\left(\mathrm{L}_1\right)\) and \(\mathrm{z}_2\) is intersection of line \(\mathrm{L}_1 \& \mathrm{~L}_2\) Circle : \((x+2)^2+(y-3)^2=1\) \(L_1: x+y-1=0 \)…
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