ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

If for some \(p , q , r \in R\), not all have same sign, one of the roots of the equation \(\left(p^{2}+q^{2}\right) x^{2}-2 q(p+r) x\) \(+q^{2}+r^{2}=0\) is also a root of the equation \(x^{2}+2 x-8=0\), then \(\frac{q^{2}+r^{2}}{p^{2}}\) is equal to-

  1. A \(271\)
  2. B \(273\)
  3. C \(274\)
  4. D \(272\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(272\)

Step-by-step Solution

Detailed explanation

\((p x-q)^{2}+(q x-r)^{2}=0\) \(x=\frac{q}{p}=\frac{r}{q}=-4\) \(\frac{q^{2}+r^{2}}{p^{2}}=272\)
Same subject
Explore more questions on app