JEE Mains · Maths · STD 12 - 13. probability
\(25 \%\) of the population are smokers. A smoker has \(27\) times more chances to develop lung cancer then a non-smoker. A person is diagnosed with lung cancer and the probability that this person is a smoker is \(\frac{ k }{10}\). Then the value of \(k\) is \(.............\)
- A \(9\)
- B \(3\)
- C \(6\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
\(E _1:\) Smokers \(P \left( E _1\right)=\frac{1}{4}\) \(E _2: \text { non-smokers }\) \(P \left( E _2\right)=\frac{3}{4}\) \(E :\) diagnosed with lung cancer \(P \left( E / E _1\right)=\frac{27}{28}\) \(P \left( E / E _2\right)=\frac{1}{28}\)…
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