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JEE Mains · Maths · STD 12 - 11. three dimension geometry

If the image of the point \( P(a,2,a) \) in the line \( \frac{x}{2}=\frac{y+a}{1}=\frac{z}{1} \) is Q and the image of Q in the line \( \frac{x-2b}{2}=\frac{y-a}{1}=\frac{z+2b}{-5} \) is P, then \( a+b \) is equal to:

  1. A 1
  2. B 2
  3. C 3
  4. D 4
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Answer & Solution

Correct Answer

(C) 3

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Detailed explanation

\(\frac{2 \lambda-a+a}{2}=-5 \mu-2 b\) and \(\frac{a+4 \lambda-a}{2}=2 \mu+2 b\) and \(\frac{2 \lambda-2 a-2+2}{2}=\mu+a\) \(\Rightarrow \lambda-\mu= b\) \(\lambda-\mu=2 a\) \(\lambda+5 \mu=-2 b\) \(\Rightarrow b =2 a\) and \(\lambda= a , \mu=- a\)…
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