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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

\(f(x)=\left\{\begin{array}{cc}\frac{\sin (x-[x])}{x-[x]} & , \quad x \in(-2,-1) \\ \max \{2 x, 3[|x|]\} & , \quad|x|<1 \\ 1 & , \quad \text { otherwise }\end{array}\right.\) where \([t]\) denotes greatest integer \(\leq t\). If \(m\) is the number of points where \(f\) is not continuous and \(n\) is the number of points where \(f\) is not differentiable, then the ordered pair \(( m , n )\) is

  1. A \((3,3)\)
  2. B \((2,4)\)
  3. C \((2,3)\)
  4. D \((3,4)\)
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Correct Answer

(C) \((2,3)\)

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\(f(x)=\left\{\begin{array}{ccc}\frac{\sin (x+2)}{x+2} & , & x \in(-2,-1) \\ \max \{2 x , 0\} & , & x \in(-1,1) \\ 1 & , & \text { otherwise }\end{array}\right.\) \(f\left(-2^{+}\right)=\lim \limits_{{h \rightarrow 0}} f(-2+h)=\lim _{h \rightarrow 0} \frac{\sinh }{h}=1\) \(f\)…
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