JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
\(\)f(x)=\left| {\begin{array}{*{20}{c}} {{{\sin }^2}x}&{ - 2 + {{\cos }^2}x}&{\cos 2x} \\ {2 + {{\sin }^2}x}&{{{\cos }^2}x}&{\cos 2x} \\ {{{\sin }^2}x}&{{{\cos }^2}x}&{1 + \cos 2x} \end{array}} \right| ,x \in[0, \pi]\(\) Then the maximum value of \(f(x)\) is equal to \(.....\)
- A \(6\)
- B \(7\)
- C \(8\)
- D \(9\)
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(\left| {\begin{array}{*{20}{c}} { - 2}&{ - 2}&0 \\ 2&0&{ - 1} \\ {{{\sin }^2}x}&{{{\cos }^2}x}&{1 + \cos 2x} \end{array}} \right| (\mathrm{R}_{1} \rightarrow \mathrm{R}_{1}-\mathrm{R}_{2} \,and \,\mathrm{R}_{2} \rightarrow \mathrm{R}_{2}-\mathrm{R}_{3})\)…
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