JEE Mains · Maths · STD 12 - 2. inverse trigonometric function
The number of solutions of the equation \(\sin ^{-1}\left[x^{2}+\frac{1}{3}\right]+\cos ^{-1}\left[x^{2}-\frac{2}{3}\right]=x^{2}\) for \(x \in[-1,1],\) and \([x]\) denotes the greatest integer less than or equal to \(x\), is ...... .
- A \(2\)
- B \(0\)
- C \(4\)
- D \(Infinite\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
Given equation \(\sin ^{-1}\left[x^{2}+\frac{1}{3}\right]+\cos ^{-1}\left[x^{2}-\frac{2}{3}\right]=x^{2}\) Now, \(\sin ^{-1}\left[x^{2}+\frac{1}{3}\right]\) is defined if \(-1 \leq x^{2}+\frac{1}{3}<2 \Rightarrow \frac{-4}{3} \leq x^{2}<\frac{5}{3}\)…
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