JEE Mains · Chemistry · STD 12 - 9. Amines
X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene. \(\mathrm{X}=\)______ g. (nearest integer)
[Given : molar mass (in \(\mathrm{g} \mathrm{mol}^{-1}\)) \(\mathrm{C}: 12, \mathrm{H}: 1\), \(\mathrm{O}: 16, \mathrm{~N}: 14]\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll}\mathrm{C}_6 \mathrm{H}_5 \mathrm{NO}_2 & \mathrm{MF}=\mathrm{C}_6 \mathrm{H}_4 \mathrm{~N}_2 \mathrm{O}_4 \\ \mathrm{MW}=123 & \mathrm{MW}=168 \\ & \therefore \frac{4.2}{168}=0.025 \mathrm{~mol}\end{array}\) \(\because\) required gm of nitro benzene…
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