JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Which one of the lanthanoids given below is the most stable in divalent form?
- A \(Ce\) (Atomic Number \(58\))
- B \(Sm\) (Atomic Number \(62\))
- C \(Eu\) (Atomic Number \(63\))
- D \(Yb\) (Atomic Number \(70\))
Answer & Solution
Correct Answer
(C) \(Eu\) (Atomic Number \(63\))
Step-by-step Solution
Detailed explanation
\(E _{ M ^{3+} / M ^{2+}}^{0} \Rightarrow Eu(-0.35) Yb(-1.05\) Hence, due to more reduction potential in \(Eu\) as compared to \(Yb\), it can concluded that \(Eu ^{2+}\) is more stable than \(Yb ^{2+}\).
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