JEE Mains · Chemistry · STD 11 - 2. structure of atom
What is the work function of the metal if the light of wavelength \(4000\, \mathop A\limits^o \) generates photoelectrons of velocity \(6\times10^5\, ms^{-1}\) from it? ............. \(\mathrm{eV}\) (Mass of electron \(= 9\times10^{-31}\, kg\) Velocity of light \(= 3\times10^8\, ms^{-1}\) Planck’s constant \(= 6.626\times10^{-34}\, Js\) Charge of electron \(= 1.6\times10^{-19}\, J\,eV^{-1}\))
- A \(0.9\)
- B \(3.1\)
- C \(2.1\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(2.1\)
Step-by-step Solution
Detailed explanation
\(hv = \phi + h{v^o}\) \(\frac{1}{2}m{v^2} = hc\left( {\frac{1}{\lambda } - \frac{1}{{{\lambda _0}}}} \right)\) \(hv = \phi + \frac{1}{2}m{v^2}\) \(\phi = \frac{{6.626 \times {{10}^{ - 34}} \times 3 \times {{10}^8}}}{{4000 \times {{10}^{ - 10}}}}\)…
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