JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The Total pressure observed by mixing two liquid \(A\) and \(B\) is \(350\,mm\,Hg\) when their mole fractions are \(0.7\) and \(0.3\) respectively.The Total pressure becomes \(410 \,mm\,Hg\) if the mole fractions are changed to \(0.2\) and \(0.8\) respectively for \(A\) and \(B\). The vapour pressure of pure \(A\) is \(...........\,mm\,Hg\). (Nearest integer) Consider the liquids and solutions behave ideally.
- A \(314\)
- B \(312\)
- C \(311\)
- D \(310\)
Answer & Solution
Correct Answer
(A) \(314\)
Step-by-step Solution
Detailed explanation
Let \(V.P.\) of pure \(A\) be \(P _{ A }^0\) Let \(V.P\) of pure \(B\) be \(P _B^0\) When \(X _{ A }=0.7 \& X _{ B }=0.3\) \(P _{ s }=350\) \(\Rightarrow P _{ A }^0 \times 0.7+ P _{ B }^0 \times 0.3=350\) When \(X _{ A }=0.2 \& X _{ B }=0.8\) \(P _{ s }=410\)…
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