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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

The Total pressure observed by mixing two liquid \(A\) and \(B\) is \(350\,mm\,Hg\) when their mole fractions are \(0.7\) and \(0.3\) respectively.The Total pressure becomes \(410 \,mm\,Hg\) if the mole fractions are changed to \(0.2\) and \(0.8\) respectively for \(A\) and \(B\). The vapour pressure of pure \(A\) is \(...........\,mm\,Hg\). (Nearest integer) Consider the liquids and solutions behave ideally.

  1. A \(314\)
  2. B \(312\)
  3. C \(311\)
  4. D \(310\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(314\)

Step-by-step Solution

Detailed explanation

Let \(V.P.\) of pure \(A\) be \(P _{ A }^0\) Let \(V.P\) of pure \(B\) be \(P _B^0\) When \(X _{ A }=0.7 \& X _{ B }=0.3\) \(P _{ s }=350\) \(\Rightarrow P _{ A }^0 \times 0.7+ P _{ B }^0 \times 0.3=350\) When \(X _{ A }=0.2 \& X _{ B }=0.8\) \(P _{ s }=410\)…
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