JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The solubility of \(Ca ( OH )_{2}\) in water is ....... . [Given : The solubility product of \(Ca ( OH )_{2}\) in water \(\left.=5.5 \times 10^{-6}\right]\)
- A \(1.77 \times 10^{-6}\)
- B \(1.11 \times 10^{-6}\)
- C \(1.11 \times 10^{-2}\)
- D \(1.77 \times 10^{-2}\)
Answer & Solution
Correct Answer
(C) \(1.11 \times 10^{-2}\)
Step-by-step Solution
Detailed explanation
\(Ca ( OH )_{2} \rightleftharpoons Ca ^{2+}( aq )+2 OH ^{-}( aq )\) \(\quad \quad \quad \quad \quad \quad \quad \quad s\quad \quad \quad \quad \quad 2s\) \(k _{ sp }= s (2 s )^{2} \Rightarrow 5.5 \times 10^{-6}=4 s ^{3}\)…
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