JEE Mains · Chemistry · STD 11 - 2. structure of atom
The radius of the \(2^{\text {nd }}\) orbit of \(Li ^{2+}\) is \(x\). The expected radius of the \(3^{\text {rd }}\) orbit of \(Be ^{3+}\) is
- A \(\frac{9}{4} x\)
- B \(\frac{4}{9} x\)
- C \(\frac{27}{16} x\)
- D \(\frac{16}{27} x\)
Answer & Solution
Correct Answer
(C) \(\frac{27}{16} x\)
Step-by-step Solution
Detailed explanation
\(Li ^{2+}\) \(r _2= x = k \times \frac{2^2}{3}=\frac{4 k }{2}\) \(Be ^{3+}\) \(r _3= y = k \times \frac{3^2}{4}\) \(\frac{y}{x}=\frac{9}{4} \times \frac{3}{4}=\frac{27}{16}\) \(y=\frac{27}{16} x\)
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