JEE Mains · Chemistry · STD 12 - 4. d and f- block elements
Preparation of potassium permanganate from \(\mathrm{MnO}_2\) involves two step process in which the 1st step is a reaction with KOH and \(\mathrm{KNO}_3\) to produce
- A \(\mathrm{K}_3 \mathrm{MnO}_4\)
- B \(\mathrm{K}_4\left[\mathrm{Mn}(\mathrm{OH})_6\right]\)
- C \(\mathrm{KMnO}_4\)
- D \(\mathrm{K}_2 \mathrm{MnO}_4\)
Answer & Solution
Correct Answer
(D) \(\mathrm{K}_2 \mathrm{MnO}_4\)
Step-by-step Solution
Detailed explanation
Preparation of \(\mathrm{KMnO}{ }_4\) \(\mathrm{MnO}_2 \xrightarrow[\mathrm{KNO}_3]{\mathrm{KOH}} \mathrm{K}_2 \mathrm{MnO}_4 \xrightarrow[\substack{\text { Oxidation in } \\ \text { Alkaline solution }}]{\text { Elecrolta }} \mathrm{KMnO}_4\)
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