JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The vapour pressure of pure benzene and methyl benzene at \(27^{\circ} \mathrm{C}\) is given as \(80 \mathrm{Torr}\) and \(24 \mathrm{Torr}\), respectively. The mole fraction of methyl benzene in vapour phase, in equilibrium with an equimolar mixture of those two liquids (ideal solution) at the same temperature is _______ \(\times 10^{-2}\). (nearest integer)
- A \(20\)
- B \(25\)
- C \(23\)
- D \(30\)
Answer & Solution
Correct Answer
(C) \(23\)
Step-by-step Solution
Detailed explanation
\(\mathrm{X}_{\text {methylbezzene }}=0.5\) \(\mathrm{Y}_{\text {mehylibenzene }}=\frac{\mathrm{P}_{\text {methylbenzene }}}{\mathrm{P}_{\text {total }}}\) \(\mathrm{Y}_{\text {mehhylibenzene }}=\frac{0.5 \times 24}{0.5 \times 80+0.5 \times 24}\)…
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