JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
In Carius method of estimation of halogen. \(0.45\,g\) of an organic compound gave \(0.36\,g\) of \(AgBr\). Find out the percentage of bromine in the compound.Molar masses : \(AgBr =188 g mol ^{-1}: Br =80 g mol ^{-1}\) )
- A \(34.04 \%\)
- B \(40.04 \%\)
- C \(36.03 \%\)
- D \(38.04 \%\)
Answer & Solution
Correct Answer
(A) \(34.04 \%\)
Step-by-step Solution
Detailed explanation
Mass of organic compound \(=0.45\,gm\) Mass of \(AgBr\) obtained \(=0.36\,gm\) \(\therefore\) Moles of \(AgBr =\frac{0.36}{188}\) \(\therefore\) Mass of Bromine \(=\frac{0.36}{188} \times 80=0.1532\,gm\) \(\therefore \% Br\) in compound…
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